3n^2=279

Solution for 3n^2=279 equation:

3n^2=279

We move all terms to the left:

3n^2-(279)=0

a = 3; b = 0; c = -279;
Δ = b2-4ac
Δ = 02-4·3·(-279)
Δ = 3348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3348}=\sqrt{36*93}=\sqrt{36}*\sqrt{93}=6\sqrt{93}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{93}}{2*3}=\frac{0-6\sqrt{93}}{6}
=-\frac{6\sqrt{93}}{6}
=-\sqrt{93}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{93}}{2*3}=\frac{0+6\sqrt{93}}{6}
=\frac{6\sqrt{93}}{6}
=\sqrt{93}
$